The number of boys in a class is twice the number of girls. A team of 8 students is to be selected with 5 boys and 3 girls in the team. In how many ways can this be done if the number of students in the class is 15?
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Answer:
Since
The number of boys in a class is twice the number of girls.
Let number of girls be 'x'.
Number of boys = '2x'.
According to statement
2x + x = 15
3x = 15
x = 5
number of girls be = 5
Number of boys = 10
Number of ways in which 5 boys and 3 girls be selected = C(10, 5) × C(5, 3)
= 252 × 10
= 2520
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Answer:2520 ways it can be done as i have shown in above pic in that manner u have to do it
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