Question

the number of carbon atoms in 1 gram of carbon carbonate

Answer 1

Answer :-

Well I think the questions should be :-

The number of carbon atoms in 1 gram of Calcium Carbonate.

◾ Solution :-

As we know mass of

Calcium atom :- 40 u

Carbon atom :- 12 u

Oxygen atom :- 16 u

→ Molecular formula of calcium carbonate .

$= CaCO_3$

♦ Hence mass of calcium carbonate

= (40)*1 + (12)*1 + (16)*3

= 40 + 12 + 48

= 100 u

♦ Now molar mass

= 100 g

** Note :- Molar mass of a substance

$= molecular/atomic \: mass \times N_A$

$N_A = 6.022 \times 10^{23}$

♦ Now Number of moles present in 1gram of Calcium Carbonate

$= \dfrac{Given\:Mass}{Molar\:Mass}$

$= \dfrac{1}{100}$

$= 0.01 \: moles$

♦ Now to find out Number of Carbon atoms.

• Number of atoms

= No. of atom/atoms present in one molecule × $N_A$ × no. of Moles

$1 \times (6.022 \times 10^23) \times 0.01$

$= 6.022 \times 10^{21} \: atoms$

Answer 2

Answer:

$=6.022X10^{21} atoms$

Explanation:

According to the question,

The number of carbon atoms in 1 gram of Calcium Carbonate.

We know mass of

Calcium atom:- 40 u

Carbon atom:- 12 u

Oxygen atom:- 16 u

The molecular formula of calcium carbonate $CaCO_{3}$

Mass of calcium carbonate

$= (40)*1 + (12)*1 + (16)*3\\\\= 40 + 12 + 48\\\\= 100 u = 100grm$

Now,

Number of moles of 1 g of CaCO3

$=\frac{Mass}{Molar mass}=\frac{1}{100}=0.01$

Since one mole of CaCO3 contains 1 mole of C atom,

So, 0.01 moles of CaCO3 contain 0.01 moles of a carbon atom.

1 mole of a carbon atom contains $=6.022X10^{23} atoms$

Hence, 0.01 moles of carbon atom contain $=6.022X10^{21} atoms$.