Chemistry, asked by hemanth453796, 3 months ago

the number of carbon atoms present in 1gram of limestone

Answers

Answered by gowsove123

1

Answer:

1g of CaCO3 will contain 6.022 * 10^23 / 100 = 6.022 * 10^21 carbon atoms.

So, the number of Carbon atoms present is

6.022 * 10^ 21.

hope it helps....

Answered by Anonymous

0

Explanation:

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