Question

The number of cars sold per day at a local car dealership, along with its
corresponding probabilities, is shown in the succeeding table. Compute the
variance and the standard deviation of the probability distribution by following the
given steps. Write your answer in your answer sheets.
Number of Cars Sold X
0
1
2
3
Probability P{x)
10%
20%
30%
20%
20%

pleaseeeee​

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Answer 1

Answer:

such a long text

sorry but I can't read it

Answer 2

Question 1) :- Abhishek purchased 140 shirts and 250 trousers @450 and @ 550 respectively. What should be theoverall average selling price of shirts and trousers …

Answer :-

we have,

→ Total price of 140 shirts = 140 * 450 = Rs.63,000 .

and,

→ Total price of 250 shirts = 250 * 550 = Rs.1,37,500 .

then,

→ Average price = (63000 + 137500) / (140 + 250) = (200500/390) = Rs.514.10 (Ans.)

Question 2) :- there are five terms in an ap the sum of these terms is 55 and the fourth term is 5 more than the sum of the first two terms find the terms of ap ?

Answer :-

we have,

→ S(5) = 55

→ T(4) - S(2) = 5

so,

→ (a + 3d) - (2a + d) = 5

→ a - 2a + 3d - d = 5

→ 2d - a = 5 --------------- Eqn.(1),

and,

→ (5/2)[2a + (5 - 1)d] = 55

→ (5/2)[2a + 4d] = 55

→ 5a + 10d = 55 ----------- Eqn.(2) ,

now, multiply Eqn.(1) by 5 and subtract from Eqn.(2),

→ (5a + 10d) - 5(2d - a) = 55 - 5*5

→ 5a + 5a + 10d - 10d = 55 - 25

→ 10a = 30

→ a = 3 .

putting value of a in Eqn.(1),

→ 2d - 3 = 5

→ 2d = 8

→ d = 4.

therefore, required AP is 3, 7, 11, 15, ___________ .

Learn more :-

If the nth term of an AP is (2n+5),the sum of first10 terms is

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