Question

The number of circular divisions on the shown screw gauge is 50. It moves 2 mm on the main scale for two complete rotations. The main scale reading is 5. The diameter of the ball is :
PLEASE ANSWER WITH A COMPLETE SOLUTION.

Answer 1

Answer:

As shown in first figure the zero error of the screw gauge is:

ZE=

50

5×0.5

=0.05mm

Least count of circular scale =

50

0.5

=0.01mm

Circular scale reading =25×0.01=0.25mm

Main scale reading =2×0.5=1mm

Actual measurement is =MSR+CSR − ZE =1+0.25−0.05=1.20mm

Answer 2

Answer:

As shown in first figure the zero error of the screw gauge is:

ZE= 5×0.5/50 = 0.05mm

Least count of circular scale = 0.5 / 50 = 0.01mm

Circular scale reading =25×0.01=0.25mm

Main scale reading =2×0.5=1mm

Actual measurement is =MSR+CSR − ZE =1+0.25−0.05=1.20mm

so , 1.20 is the correct ans

Explanation:

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