Question

The number of Cl-

and Ca+2 ions in 222g. of CaCl2

are​

Answer 1

The formula mass of Ca2+ is 40g while that of Cl- is 35.5g hence the formula mass of CaCl2 is 111g( 40+(35.5*2)) since there are two ions of cl- in CaCl2.

If 111g =6.022*10^23ions

Therefore 222g of CaCl2=(222*6.022*10^23)/111

Ans=1.205*10^24

There are 1Ca2+ in one unit of CaCl2 hence there are 1.205*10^24ions.

Similarly there are 2Cl- in one unit of CaCl2 hence there are( 1.205*10^24/2)=6.03*10^23 ions.

The number of Ca2+ is 1.205*10^24ions while that of Cl- is 6.03*10^23ions present in 222g of CaCl2.

Hope it helps

Mark it as BRAINLIEST if you are satisfied with the answer

Answer 2

Answer:The number of Ca2+ is 1.205*10^24ions while that of Cl- is 6.03*10^23ions present in 222g of CaCl2. Hence, there are 1.2044 X 1024 Ca2+ ions and 2.4088 X 1024 Cl- ions in 222 g of CaCl2.Hope it helps please mark me as brainliest if you are satisfied