the number of coins of radius 0.75 and thickness 0.2 CM be melted to make a right circular cylinder of height 8 cm and base radius 3 cm is
Answers
Answered by
16
Volume of cylinder=πr²h
heights=8cm
Radius=3cm
volume=π3²×8=72π cm³
coin is also a cylindrical shape
Radius=0.75cm
Thickness=0.2cm
Volume=π0.75²×0.2=π×0.75×0.75×0.2
Coins will be
= whole coins volume/one coin volume
=72×π/π×0.75×0.75×0.2
=72×100×100×10/75×75×2
=7200000/11250
=640 coins
THANKS sis
heights=8cm
Radius=3cm
volume=π3²×8=72π cm³
coin is also a cylindrical shape
Radius=0.75cm
Thickness=0.2cm
Volume=π0.75²×0.2=π×0.75×0.75×0.2
Coins will be
= whole coins volume/one coin volume
=72×π/π×0.75×0.75×0.2
=72×100×100×10/75×75×2
=7200000/11250
=640 coins
THANKS sis
Hunnyshah:
mention not
Similar questions