Question

The number of columns in a state table for a
sequential circuit with m flip-flops and n inputs is

1. m + n 2. m + 2n
3. 2m + n 4. 2m + 2n​

Answer 1

It's 2m+2n because .

If there are m flip-flops, there should be 2m nodes. If there are n inputs, then each node will have 2n.

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Answer 2

We need 2m + n columns in an exceedingly state table for a sequential circuit having m flip-flops along with n inputs.

Explanation:

• Here we all know that, for every of the M flip-flops, we've to put in writing this because the next state of flip-flop.

• So, for M=1, we should always have 2 entries, one for this state and one of the consequent states.

• So, for M flip-flops, there'll be 2M columns for flip-flop state data.

• If there's one input, then there'll be one column.

• so for N input, we should always have N columns.

• so, total columns in state table = 2M + N

Thus, the proper possibility is C >> we want 2m + n columns in an exceedingly state table for a sequential circuit having m flip-flops and n inputs.