Question

The number of consecutive zeors in the ending of number 2^4×3^2x5^7×7^3​

Answer 1

Answer:

There are 4 consecutive zeroes in the ending of the given number.

Step-by-step explanation:

2^4 = 2×2×2×2 = 16

3^2 = 3×3 = 9

5^7 = 5×5×5×5×5×5×5 = 78125

7^3 = 7×7×7 = 343

Hence, 2^4×3^2x5^7×7^3 = 16×9×78125×343 = 3858750000.

Since there are 4 consecutive zeroes after 385875 so the answer is 4.

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