The number of consecutive zero in 2^3 ×5^4×3^4×7 is 3
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"We take the minimum number of 2s and 5s [Logically and theoretically too]. So, the number of zeros in X will be 3. In your question, there are three 2s and four 5s. Since there are only three 2s, there will be only one three consecutive zeros.
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