Question

the number of consecutive zeros in 2 raise to 7 into 3 raise to 9 into 5 raised to 4 into 9 raise 11

Answer 1

prime factorization of 10 consists of 2 and 5

for a number to end with zero its prime factorization should be of the form 2^n * 5 ^m

N = 2^7 * 3^9 * 5^4 * 9^11

   = 2^7 * 3^9 * 5^4 * (3^2)^11

   = 2^7 * 3^(9+22) * 5^4

   = 2^7 * 3^31 * 5^4

here the number has 4 zeroes

as power of 5 is the lowest and is 4

Please mark my answer as the brainliest