Question

the number of covalent bond in 8.5 g of NH3?​

Answer 1

Answer:

12.05\times 10^{23}12.05×10

23

Explanation: According to Avogadro's law, 1 mole of every substance contains avogadro's number of particles (6.023\times 10^{23})(6.023×10

23

) and weigh equal to the molecular mass.

Molecular mass of NH_3NH

3

= 17 g

17 g of NH_3NH

3

contains=(6.023\times 10^{23}(6.023×10

23

molecules of NH_3NH

3

1 molecule of NH_3NH

3

contains= 4 atoms

17 g of NH_3NH

3

contains=4\times 6.023\times 10^{23}=24.1\times 10^{23}4×6.023×10

23

=24.1×10

23

atoms

8.5 g of NH_3NH

3

contains=\frac{24.1\times 10^{23}}{17}\times 8.5=12.05\times 10^{23}

17

24.1×10

23

×8.5=12.05×10

23

atoms.