the number of covalent bonds present in 8g CH2 are
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Answer:
1.204 × 10^24
Explanation:
1mole CH4 = 16 gram
8 g CH4 = 1/2 mole CH4
4 covalent bonds in 1 molecule of CH4
1/2 mole CH4 = 3.011 ×10^23 molecules of CH4
So number of covalent bonds in 8 g CH4 = 3.011× 10^23 × 4 = 1.204 × 10^24
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