The number of days required by A, B and C to work individually is 6, 12 and 8 respectively. They started a work doing it
alternatively. If A has started then followed by B and so on, how many days are needed to complete the whole work?
Answers
Answered by
0
Step-by-step explanation:
Lcm of 6,12,8= 24
A = 24/6 = 4 units in one day
B = 24/12 = 2 units in one day
C = 24/8 = 3 units in one day
in two days = 4+2+3= 7
in 6 days= 15 units
remaining = 15-24= 9
total no of days needed = 6+1 = 7 days
Answered by
2
Answer:
8
Step-by-step explanation:
Lcm of 6,12,8- 24
A 24/6= 4 units in one day
B 24/12= 2 units in one day
C 24/8-3 units in one day
in two days = 4+2+3 = 9
in 6 days= 18 units
remaining = 18-24= 6
total no of days needed = 6+2=8 days
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