Math, asked by anish7192, 9 months ago

The number of days required by A, B and C to work individually is 6, 12 and 8 respectively. They started a work doing it
alternatively. If A has started then followed by B and so on, how many days are needed to complete the whole work?​

Answers

Answered by MASTERMIND777
0

Step-by-step explanation:

Lcm of 6,12,8= 24

A = 24/6 = 4 units in one day

B = 24/12 = 2 units in one day

C = 24/8 = 3 units in one day

in two days = 4+2+3= 7

in 6 days= 15 units

remaining = 15-24= 9

total no of days needed = 6+1 = 7 days

Answered by manojkumardaida5
2

Answer:

8

Step-by-step explanation:

Lcm of 6,12,8- 24

A 24/6= 4 units in one day

B 24/12= 2 units in one day

C 24/8-3 units in one day

in two days = 4+2+3 = 9

in 6 days= 18 units

remaining = 18-24= 6

total no of days needed = 6+2=8 days

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