Math, asked by sibdhusharavuri6003, 9 months ago

The number of decimal places after which the decimal expansion of rational number 91/2^6*5^5 will terminate after

Answers

Answered by seemyadav
4

Answer:

after 6 decimal places.

Step-by-step explanation:

the highest degree is two.

in the denominator: 2^6×5^5

= 91×5/2^6×5^5×5

= 455/(2×5)^6

= 455/(10)^6

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Answered by FelisFelis
0

The number of decimal places after which the decimal expansion  will terminate after is 6 decimal place.

Step-by-step explanation:

Consider the provided rational number.

\dfrac{91}{2^6\times5^5}

Multiply the numerator and denominator by 5.

\dfrac{91}{2^6\times5^5}\times\dfrac{5}{5}

\dfrac{455}{2^6\times5^6}

\dfrac{455}{(2\times5)^6}

\dfrac{455}{10^6}

Since the power of 10 is 6.

Thus, the number of decimal places after which the decimal expansion  will terminate after is 6 decimal place.

#Learn more

The decimal representation of 11/40 will:-

a) terminate after 1 decimal place

b) terminate after 2 decimal places

c) terminate after 3 decimal places

d) not terminate

explain also​

https://brainly.in/question/12566594

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