Question

The number of diagonal in a regular octagon is ...................................?

Answer 1

Number of diagonal=n(n-3)/2
=8(8-3)/2
=8×5/2
=4×5
=20
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Answer 2

$<h2><font color = red > hey there$



$<font color = black > here we go....$



First we have to find the sum of all the angles of a octagon.

We know that octagon has 8 sides.


using the formula ,

$(n - 2) \times 180$


Here n =8

$(8 - 2) \times 180$



$6 \times 180 = 1080$



Now , to find diagonal we use the formula :-


$\frac{n(n - 3)}{2} = number of diagonal$


Take number of diagonals = n


$\frac{8(8 - 3)}{2 } \\ \\ \frac{40}{2} = 20 \: diagonals$



Hope it helps you

Thanks for asking....


@ Prabhudutt