The number of different arrangements that begin
with the letter R of the word WORLD are
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9
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There are 5 vowels in the given word I,N,D,E,P,E,N,D,E,N,C,E
4E ′ s and I s
They have occur together we treat them as single object
We treat EEEEI as a single object.
So our letters become
EEEEIND ,PNDNC
We arrange them now
Arranging 5 vowels:
Since vowels are coming together, they can be
EEEEIIEEEEEEIEE
and so on.
In EEEEI there are 4E
Since letter are repeating, we use the fomula=n!/p¹!p²!p³
Total letter=n=5
As 4E are there,p 1 =4
Total arrangements=5!/4!
Arranging remaining letters
Numbers we need to arrange=7+1=8
Since letter are repeating, we use this formula=n¹!/p¹!p²!p³
Total letters=n=8
As 3N,2D
⇒p 1
=3,p 2=2
Total arrangements= 3!2!/8!
=8×7×6×5×2×5=16800
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7
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thanks for the free point BTW I don't know the correct answer of this
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