Question

The number of different necklaces formed by using 2n identical diamonds

Answer 1

Number of identical diamonds from which we have to make necklace = 2 n

Possible number of arrangement of 2 n identical diamonds to form a necklace =$\frac{(2n)!}{(2n)!}=1$

As necklace will appear same in clockwise as well as anticlockwise Direction.

So only 1 necklace can be formed by using 2 n identical diamonds.