Math, asked by reuben2006, 9 months ago

The number of different prime factors of N=2^3 x 3^5 x 5^7 x 7^5 is:
A) 20
B)4
C) 15
D) 16​

Answers

Answered by Vikasghodke
0

Answer:

the answer for the question is (B)

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