Math, asked by jesusmo6658, 11 months ago

The number of distinct real roots of the equation sin pi x= x^2-x+5/4

Answers

Answered by ayushsharma19
2
x=11 is the distinct real roots of the equation
Answered by anishaelsasl
0

Answer:

The number of distinct real roots of the equation sin\pi x=x^{2} -x+\frac{5}{4}   is  1

Step-by-step explanation:

Given equation:

sin\pi x=x^{2} -x+\frac{5}{4}

sin\pi x=(x-\frac{1}{2})^{2}  +1

sin\pi x=1

\pi x=sin^{-1} (1)

\pi x=\frac{\pi }{2}

x=\frac{1}{2}

As observed,

sin\pi x=1  and x=\frac{1}{2}

Hence, the equation sin\pi x=x^{2} -x+\frac{5}{4} has only 1 distinct root and that is x=\frac{1}{2}

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