Math, asked by sanjayvenki201, 3 months ago

The number of distinct sequences we can make using the letter ‘J’ three times and the letter ‘K’ five times (eg. JJJKKKKK,JJKKJKKK,etc.) is

Answers

Answered by sreemo207

5

Answer:

56

Step-by-step explanation:

no of characters= 3J, 5K = 8 characters

permutations = 8!/3!*5! = 56

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