the number of electric lines of force that radiate outwards from 8.85 uc in vacuum is
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Explanation:
Hi there :)
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>Number of field lines is proportional the flux emanating from a charge source in unit area;
>Flux is given by: [Ф = E x A = q /ε ]
q= net charge for which flux is calculated
ε= permittivity of free space
E = electric field intensity
A = area
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Now, in the given question q = 1C and ε(in vaccum) = 10^{-9} / (4π x 9)
so
Ф = 9 x 10^{9} / (4π)
≈ 3/4 x 10^{9}
≅ 7.5 x 10^{9} [ ans.]
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