the number of electro present in Al3+ ion is
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10 because
Electronic configuration of Al is 2,8,3.
It has already loosen the 3 electrons to become stable and acquire positive charge.
Now electrons left are 2,8
Thus total electrons 2+8=10
Hope it helps
Electronic configuration of Al is 2,8,3.
It has already loosen the 3 electrons to become stable and acquire positive charge.
Now electrons left are 2,8
Thus total electrons 2+8=10
Hope it helps
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