Question

The number of electron in nitrogen that has n + l + m value as odd number

Answer 1

there are in number of 7 in series nitrogen

Answer 2

The number of electrons in nitrogen having $n + l + m$ as an odd number would be 3 electrons.

Explanation:

Nitrogen contains $1s^{2} 2s^{2} 2p^{3}$

In the case of $1s$ electrons,

$n = 1$

$l = 0$

$m = 0$

∵  $n + l + m$

= $1 + 0 + 0$

= 1

In the case of $2s$ electrons,

$n = 2$

$l = 0$

$m = 0$

∵  $n + l + m$

$= 2 + 0 + 0$

= 2

In the case of $2p$ electrons,

$n=2$

$l=1$

$,m=+1,0, -1$

∵  $n + l + m$

$= 2 + 1 + 0$

= 3

Thus, the number of electrons in nitrogen having $n + l + m$ as an odd number would be 3 electrons.

Learn more: Electrons

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