Question

the number of electrons flowing through a section of a conductor in one neno second, if the current through the conductor is 0.75A

Answer 1

I=Q/t
Q is charge in coulombs
I=1 amp
t=1 sec

so Q must be 1 coulomb
we know one electron has -1.6 x 10^(-19) coulombs negative is just the charge so we can ignore it.

(# electrons) * (1.6 x 10^(-19) coulombs) = 1 coulombs
(# electrons) = 1/(1.6 x 10^(-19))

Hop e it help s.