Question

The number of electrons having
having n+l=5 in V atom is.
please answer fast ​

Answer 1

Answer:

Choose, n value always greater or equal to “(l+1)”. In this case,

( n+l ) = 5

l replaced by (l+1).

(n+(l+1))=6

maximum value of n = 3

and, l+1 = 3

therefore, l =2 i.e. d orbital

ANSWER 3d orbital

Explanation:

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Answer 2

Atomic number of V is 23.

Let's write the electronic configuration,

$1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{3}$

We know, the values of l are

0 for s orbital

1 for p orbital

2 for d orbital

3 for f orbital

Now, we'll find the value of (n+l)

=> 1s - (1+0) = 1

=> 2s - (2+0) = 2

=> 2p - (2+1) = 3

=> 3s - (3+0) = 3

=> 3p - (3+1) = 4

=> 4s - (4+0) = 4

=> 3d - (3+2) = 5

The (n+l) value is 5 for only 3d electrons.

The number of electrons in 3d of V are 3.

Answer is 3 electrons..