The number of electrons in 0.2 mol of Al3+ ion is
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Answered by
1
Explanation:
no. of atoms Al3+ = 0.2 × 6.022 × 10^23
So, no of electrons = 2 × 6.022 ×10^23
= 1.2044 × 10^24 e
Answered by
0
Answer:
correct answer is NA (NA is Avogadro's no )
Explanation:
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