Question

The number of electrons in 3.1 mg No3-​

Answer 1

Answer:

Answer : The number of electrons in 3.1 mg moles of NO-3  is 9.64 X 10^20 electrons.

Solution : Given,

Mass of NO-3  = 3.1 mg

Molar mass of NO-3  = 62 g/mole

First we have to calculate the moles of NO-3

Moles of NO-3  = GIVEN MASS/MOLAR MASS = 3.1*10-3G/ 62G/MOLE = 0.05X10^-3 MOLES

1 mole of NO-3  has 6.002 X 10^23  molecule of NO-3

0.05 moles of NO-3  has 6.002 X10^23  molecule of NO-3

Now we have to calculate the number of electrons in NO-3

The number of electrons present in 1 molecule of NO-3  is, NO-3

= (7) + 3(8) + 1 = 32 electrons

Number of electrons present in 1 molecule of NO-3  = 32 electrons

Number of electrons present in  molecule of NO-3  = 9.64 X 10^20  electrons

Therefore, the number of electrons in 3.1 mg moles of  is 9.64 x 10^20  electrons.

Explanation: