The number of electrons in 3.1mg NO3- is?
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Answered by
39
The chemical name of N03- is Nitrate.
It is a polyatomic ion with molecular mass of 62.0049 u.
Number of electrons in 3.1 mg N03- is:
Number of NO3 molecule = 3.1/62 x 6.022 x10^23
= 3.011x10^22
Then, total number of electrons in NO3
= 32 electrons
= 32 x3.011x10^22
It is a polyatomic ion with molecular mass of 62.0049 u.
Number of electrons in 3.1 mg N03- is:
Number of NO3 molecule = 3.1/62 x 6.022 x10^23
= 3.011x10^22
Then, total number of electrons in NO3
= 32 electrons
= 32 x3.011x10^22
Answered by
2
Answer:
Number of NO3 molecule = 3.1/62 * 6.022 *10^23 = 3.011*10^22 then, total number of electrons in NO3 = 32 electrons = 32 *3.011*10^22 =96.352*10^22
Explanation:
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