The number of electrons in Na, having n+l = 3
(A) 4 (B) 6 (C) 7 (D) 8
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(D)8
The electronic configuration of Na atoms
1s²2p63s²3p⁴
The orbitals with n+1 =3 are 2p and 3s so 8electroms in Na have n+1=3
D is correct answer
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