The number of electrons in oxygen atom in 0.3 gram molecule of mohr's salt
(FeSO4.(NH4)2SO4.^H20)
Answers
Answered by
1
Answer:1gram molecule means 1molecontains 9 oxygen atoms it means contain 8×9=72 electrons
Explanation:
1 gram molecule,72e-,0.3gram molecule contain,72×0.3=21.6e-
Answered by
5
Dear Student,
◆ Answer -
2.023×10^25 electrons
● Explanation -
One molecule of Mohr's salt (FeSO4.(NH4)2SO4.6H20) contains 4 + 4 + 6 = 14 atoms of oxygen.
O.3 g of Mohr's salt cotains 0.3 × 6.022×10^23 = 1.8066×10^23 molecules.
Therefore, O.3 g of Mohr's salt cotains 14 × 1.8066×10^23 = 2.53×10^24 oxygen atoms.
One oxygen atom contains 8 e-. Therefore, total electrons in Oxygen atoms are 8 × 2.53×10^24 = 2.023×10^25 electrons.
Thanks dear...
Similar questions