the number of electrons involved when 1 mole of h2o2 decomposes as
Subhikshamurari:
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Answered by
19
H2O2 --> 2 H2O + O2
mole of O2 = 11.2 / 22.4 = 0.5 mol
mole of H2O2 = 2/1 * mole of O2 [ratio of coefficients = ratio of moles]
= 2 * 0.5 = 1 mol
mole of O2 = 11.2 / 22.4 = 0.5 mol
mole of H2O2 = 2/1 * mole of O2 [ratio of coefficients = ratio of moles]
= 2 * 0.5 = 1 mol
Answered by
10
Hey dear,
● Answer -
1 mol of e-
● Explaination -
Decomposition of H2O2 takes place as follows -
H2O2 --> 2OH• --> H2O + 1/2 O2
Writing half reactions,
OH• + H+ + e- --> H2O
OH• --> 1/2 O2 + H+ + e-
From this, we can say that - for each molecule of H2O2 decomposed 1 e- is required.
For decomposition of 1 mole of H2O2, 1 mole of e- will be required.
Thanks for asking..
● Answer -
1 mol of e-
● Explaination -
Decomposition of H2O2 takes place as follows -
H2O2 --> 2OH• --> H2O + 1/2 O2
Writing half reactions,
OH• + H+ + e- --> H2O
OH• --> 1/2 O2 + H+ + e-
From this, we can say that - for each molecule of H2O2 decomposed 1 e- is required.
For decomposition of 1 mole of H2O2, 1 mole of e- will be required.
Thanks for asking..
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