Question

The number of electrons passing through a cross section of uniform heater wire in one minute if it carries of 9.6 a is

Answer 1

We know that ,

q = ± ne

and

q = it

So, it = ± ne

9.6 × 60 secs = n × 1.6 × 10^ (-19)

n = 360 × 10^(19)

n ≈ 3.6 × 10^ (21)