Question

The number of electrons passing through a metallic wire in one minute, if it carries a current of 8A, will be
(1) 2 * 10^20
(2) 2 * 10^21
(3) 3 *10^20
(4) 3 *10^21​

Answer 1

Answer:

answer option (4) = 3*10^21

Step-by-step explanation:

The current is defined as rate of flow of

charged particles, i.e., I =Q/t

Here, I = 8 A and t = 1 min = 60 s

So, 8 A =Q/60 s

This gives: Q= 480 C

Now, Q = N x e, where N is the number of electrons and e is the electronic charge of

value = 1.6 × 10^-19 C

N=Q/e =480/1.6 x 10 ^ -19

final answer N= 3.0 x 10^21