The number of electrons passing through a metallic wire in one minute, if it carries a current of 8A, will be
(1) 2 * 10^20
(2) 2 * 10^21
(3) 3 *10^20
(4) 3 *10^21
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Answer:
answer option (4) = 3*10^21
Step-by-step explanation:
The current is defined as rate of flow of
charged particles, i.e., I =Q/t
Here, I = 8 A and t = 1 min = 60 s
So, 8 A =Q/60 s
This gives: Q= 480 C
Now, Q = N x e, where N is the number of electrons and e is the electronic charge of
value = 1.6 × 10^-19 C
N=Q/e =480/1.6 x 10 ^ -19
final answer N= 3.0 x 10^21
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