The number of electrons present in 1.6g of CH4 is
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CH4 is therefore 16 grams per mole. So, we want to know how many electrons are in 0.1 moles of CH4 molecules. If I have 0.1 moles of CH4, I must have 0.1 moles of carbon atoms and 0.4 moles of hydrogen atoms. One mole is 6.02 * 10^23 entities....
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HEY FRIEND HERE YOUR ANSWER
From the formular
N=n*NA
where n =mass/mr
hence
N=m/mr*NA
N; number of electron
m;mass of methane
mr; molar mass of methane
*multiplication
NA; Avogadros constant =6.022*10^23
There fore
N=1.6/CH4*6.022*10^23
N =1.6/16*6.022*10^23
N=6.022*10^22electrons
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS.....
From the formular
N=n*NA
where n =mass/mr
hence
N=m/mr*NA
N; number of electron
m;mass of methane
mr; molar mass of methane
*multiplication
NA; Avogadros constant =6.022*10^23
There fore
N=1.6/CH4*6.022*10^23
N =1.6/16*6.022*10^23
N=6.022*10^22electrons
I HOPE IT'S HELP YOU
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS.....
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