Question

The number of electrons removed from the body in order to produce positive charge of 4.8 ×10^_19c a)3 b) 5 c)7 d)9​

Answer 1

Answer:

The magnitude of charge on each electron is qe=1.6×10−19C. 

The body has a positive charge that means it has a deficiency of electrons. 

Total charge on the body is: q=n×qe=8×10−19C which implies n=5.

Answer 2

Answer:

The number of electrons removed from the body in order to produce a positive charge of 4.8 ×10⁻¹⁹C is 3.i.e. option (a).

Explanation:

The total charge of electrons present in an atom is the number of electrons multiplied by the charge on an electron.i.e.

                  $Q=ne$         (1)

Where,

Q=total charge of electron present in an atom

n=number of electrons

e=charge on an electron=1.6×10⁻¹⁹C

And we know that,

The number of electrons in a neutral atom is equal to the number of protons present in an atom.

So, as per question

Q=4.8 ×10⁻¹⁹C

By placing the value of Q and e in equation (1) we get;

$4.8 \times 10^-^1^9=n\times 1.6\times 10^-^1^9$

$n=\frac{4.8\times 10^-^1^9}{1.6\times 10^-^1^9}=3$

Hence, the number of electrons removed from the body in order to produce a positive charge of 4.8 ×10⁻¹⁹C is 3.i.e.option(a).