Question

the number of electrons transferred from one atom to another during Bond formation in barium sulphide is ​

Answer 1

Answer:

Strontium is a group 2 metal and we know that group 2 metals typically show an oxidation state of +2. So , we expect the compound to be Sr

+2

S

−2

. Note that sulphur also can show an oxidation state of -2. So, clearly 2 electrons are transferred from Sr to S.

Answer 2

The no of electrons transferred during Bond formation in barium sulphide is ​Two (2).

- Barium is a 2nd group element.

- Sulphur is a 16th group element.

- The formula of barium sulphide is BaS.

- During its formation, barium loses 2 electrons and forms Ba²⁺ ions.

- Sulphur gains these two electrons to form S²⁻.

- Due to the combination of these two ions, BaS is formed.

- hence, there is a transfer of only 2 electrons from one atom to another.