The number of elements in the set A={(a,b): 2 a square + 3 b square equals to 35,a,b€z} where z is the set of all integers
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7
Given:
set A={(a,b): 2 a² + 3 b² = 35 , a, b € z
Z is the set of all integers.
To Find:
The number of elements in A.
Solution:
- We have 2a² + 3b² = 35
- We can see that 2a² > 0
Therefore,
- 3b² < 35
- b² <35/3
- b² < 11
- b² = { 1 , 4, 9}
Similarly,
- 2a² < 35
- a² < 35/2
- a² = { 1, 4, 9, 16 }
Let a² = 1
- 3b² = 33
- b² = 11 , not possible
Let a² = 4
- 3b² = 27
- b² = 9, possible
- Possible solutions: (2,3) , (-2,3) , (-2,-3) and (2,-3)
Let a² = 9
- 3b² = 17 , not possible
Let a² = 16
- 3b² = 3
- b² = 1
- Possible solutions : (4,1) , (4,-1) , (-4,-1) and (-4,1)
The number of elements in the set A={(a,b): 2 a square + 3 b square equals to 35,a,b€z} is 8.
Answered by
0
Answer:
8 answer
(-2,3)(2,3)
Step-by-step explanation:
(-1,2)(2,4)
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