Question

the number of elements in the set a={(a,d):2a²+3b²=35,a,bEZ},where z is the set of all integers,is:​

Answer 1

Answer:

B

8

(a,b):2a

2

+3b

2

=35,a,b∈Z

⟹2(±2)

2

+3(±3)

2

=35 and 2(±4)

2

+3(±1)

2

=35

∴(a,b)=(2,3),(2,−3),(−2,−3),(−2,3),(4,1),(4,−1),(−4,−1),(−4,1)

i.e. 8 elements

Answer 2

sorry ????don't know this