Question

The number of elk varied inversely as the number of deer and directly as the number of antelope. When there are 75 elk, there were 85 deer and 15 antelope. Howe many deer were there when there were 20 elk and 30 antelopes?

Answer 1

Answer:

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Answer 2

Solution :-

Let the number of elk are E and number of deer are D and number of antelope are A .

so,

→ E ∝ 1/D

→ E = k * (1/D) -------- (1)

and,

→ E ∝ A

→ E = k * A -------- (2)

where k is constant .

then, from (1) and (2) ,

→ E = k * (A/D)

→ 75 = k * (15/85)

→ k = 5 * 85

→ k = 425

therefore, when E = 20 and A = 30,

→ E = k * (A/D)

→ 20 = 425 * (30/D)

→ D = (425 * 3)/2

→ D = 637.5

→ D ≈ 637 (Ans.)

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