Math, asked by bhanukumar6508, 11 months ago

The number of equations of the form ax*2+bx+2=0 that can be formed if the equation have real roots is

Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

The discriminant of a quadratic equation D, is given by

D = b2 – 4ac 

It is determined from the coefficients of the equation ax2 + bx + c = 0. 

The value of D reveals what type of roots the equation has.

If D is greater than 0, we get real roots

For ax2 + bx + 2 = 0 

The discriminant = b2 – 4(a)(2)

                              = b2 – 8a

Equating this to 0

b2 – 8a = 0

8a = b2

a = b2/8

a and b are positive integers and b is less than 6

the values that b can take include: 1, 2, 3, 4, 5

when

b =1, a = 1/8

b =2, a = 4/8 = ½

b = 3, a = 9/8

b =4, a = 16/8 = 2

b = 5, a = 25/8

Thus there cab be 4 real roots

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