Question

The number of factors of 21.32.53 are​

Answer 1

Step-by-step explanation:

These are certain basic formulas pertaining to factors of a number N, such that,

N= paqbrc

Where, p, q and r are prime factors of the number n.

a, b and c are non-negative powers/ exponents

Number of factors of N = (a+1)(b+1)(c+1)

Product of factors of N = N No. of factors/2

Sum of factors: ( p0+p1+...+pa) ( q0+ q1+....+qb) (r0+r1+...+rc)/ (pa-1)(qb-1)(rc-1)