Question

the number of first increasd by 20% and then it's decreased by 20% .find the net increase or decrease percent?

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Answer 1

Answer:

let the number be x

1st Case, increased by 20%

X + X*20/100

6X/5

2nd case, decreased by 20%

6X/5 - 6X/5 * 20/100

6X/5 - 6X/25

24X/25

Net Change = X - 24X/25

= X/25

so net decrease percentage = ((X/25) / X) *100

= 4%

Answer 2

Let the number = 100

Increase in number = 20% of 100

= $\frac{20}{100} \times 100 \: = \: 20$

Increased number = 100 + 20 = 120

The resulting number decreased by 20%

$decrease \: in \: number \: = \: \frac{20}{120} \: \times 120 = 24$

New number = 120 - 24 = 96

Now net decrease = 100 - 96 = 4

$net \: percent \: of \: decrease \: = \: \frac{net \: decrease}{original \: number} \: \times \: 100$

$\: \: \: \: \: \: \: \: \: \: = \frac{4}{100} \times 100 \: = 4$

So your answer is 4%

hope it helps you...