Question

the number of four legged pets in a locality were 2 more than three times the number of two legged pets if the total number of legs of the pets in the locality is 358 than find the number of four legged pets ?

Answer 1

Let the four no. of legged pets be x
and no. of two legged pets be y
from 1st condition
3y-x = 2
from 2nd condition
4x + 2y = 358
x = 3y-2
put the value of x in eqation 2
4(3y-2)+2y=358
12y-8+2y=358
14y-8=358
14y=350
y=25
put the value of x in eq. 1
3×25-x=2
75-x=2
x=75-2
x=73

Therefor no. of four legged pets is 73

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Answer 2

Answer:

Step-by-step explanation:

Let the no. of 2 legged pet in the locality be x , then the no. of 4 legged pets in the locality would be 3x + 2

Total no. of pets = 358

Therefore  x + 3x + 2= 358

                  x + 3x = 358 - 2

                  4x = 356

                  x = 356 ÷ 4

                  x = 89

no. of 2 legged pet in the locality = 89

no. of 4 legged pets in the locality = 3x + 2                                                    

= 3 × 89 + 2                                             = 267 + 2                                           

= 269

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