Question

The number of fundamental particles in He4 is X and the number of fundamental particles in C14 is Y. The value of Y – X is?
1.10
2.14
3.6
4.20

Answer 1

Answer:-

Option 2) 14

Explanation:-

Electrons, neutrons and protons are called as the fundamental particles of an atom.

So no.of fundamental particles in C14 (Y)  is No.of electrons +No.of nucleons (Protons + Neutrons) = 6 + 14 =20

No.of fundamental particles in He4 (X) is No.of electrons + No.of nucleons

(Protons + Neutrons) = 2 + 4 = 6

Y-X = 20 - 6 = 14

Answer 2

Answer:

The value of $Y-X$ is $14$ So, option($2$) is correct.

Explanation:

Let fundamental particles in helium $=x$

$x=n+p+e\\=2+2+2\\=6$

Let fundamental particles in C$14=y$

$y=n+p+e\\=(A-Z)+(A)+(A)\\=(14-6)+6+6\\=8+6+6$

$\therefore y=20$

Hence, the difference between the two values are

$Y-X=20-6\\=14$