Question

the number of glucose molecules present in 10ml of decimolar solution is​

Answer 1

Answer:

Given, Molarity =0.1 M; V=10 ml=0.01 litre

Number of moles =Molarity×volume (in liters)

=0.1×0.01

=10

−3

moles

Number of Molecules =moles×Avogadro number(N

A

)

=10

−3

×6.0×10

23

=6×10

20

molecules

Answer 2

Explanation:

Given, Molarity =0.1 M; V=10 ml=0.01 litre

Number of moles =Molarity×volume (in liters)

=0.1×0.01

=10

−3

moles

Number of Molecules =moles×Avogadro number(N

A

)

=10

−3

×6.0×10

23

=6×10

20

molecules

So, the correct option is A