Question

The number of glycosidic bonds associated with DNA of diploid human cell are
1. 6.6 × 10^9
2. 2 × 6.6 × 10^9
3. 3.3 × 10^9
4. 3.3 × 10^9 - 2

Please explain

Answer 1

The number of glycosidic bonds associated with DNA of diploid human cell are

1. 6.6 × 10^9

2. 2 × 6.6 × 10^9

3. 3.3 × 10^9

4. 3.3 × 10^9 - 2

Answer: Option 2

Reason for the answer: The diploid genome of human DNA is 6.6 x 10^9 base pairs.Also aglycosidic bond is established between C at the first position of sugar and N at 1stposition of pyrimidine or N at the 9thposition of purine and the 1st base pair has 2 glycosidic bonds. So total number of glycosidic bond in diploid human cell are 2* 6.6 x 109 i.e. 2 option

Answer 2

The human DNA has a diploid genome of 6.6 *10^9 base pairs.

The C at the first position of sugar forms a glycosidic bond with N at the ninth position of pyrine, or N at the first position of pyrimidine.

Since one base pair has two glycosidic bonds, the total number of glycosidic bonds associated with the DNA of diploid human cell is 2* 6.6* 109.