Question

The number of gram atom of oxygen in 6.02 × 10²⁴ CO molecules is _______.
(A) 1
(B) 0.5
(C) 5
(D) 10

Answer 1

Answer:

option is b.

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Answer 2

Answer:

Mass=280 gm.

Explanation:

we know the formula of number of moles

number of moles (n)=$\frac{No.\ of\  particles}{avagadro\ number}$

avagadro number=$6.02\times10^{23}$

No.of particles=$6.02\times10^{24}$

number of moles (n)=$\frac{6.02\times10^{24} }{6.02\times10^{23} }$

number of moles (n)=10..................(1)

There is one more formula for number of moles

number of moles=$\frac{mass}{molar mass}$.....................(2)

molar mass of CO is =12+16=28.....................(3)

using (1),(2) and (3) we get

$10=\frac{mass}{28}$

Mass of carbon monoide in grams is=280 gm.