Question

the number of gram equivalent of H3PO4 present in 0.1 molar 250 ml solution is?​

Answer 1

NORMALITY = BASICITY OF ACID * MOLARITY

BASICITY OF H3PO4 = 3

N= 3*0.1

=0.3N

NORMALITY = NO. OF GRAM EQUIVALENTS/ VOLUME

WE KNOW NORMALITY = 0.3

VOLUME = 250 ML = 0.25L

NO OF GRAM EQUIVALENTS = 0.3 * 0.25

= 0.075