Question

the number of gram molecule of oxygen in 6.02 ×10^24 carbon monoxide molecules?
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Answer 1

Explanation:

1 mole CO equivalent to 6.02x10^23 molecules of CO contain 6.02x10^23 atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen. Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2 molecule.

Answer 2

Answer:

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